Problem 1
A school orders 11 packs of pencils with 8 pencils in each pack. It gives out 27 pencils on the first day. How many pencils are left?
Answer: 61 pencils
- First find the total pencils ordered: 11 × 8 = 88.
- Then subtract the pencils already given out: 88 - 27 = 61.
- The question is multi-step because multiplication comes before subtraction.
How to explain it: A good parent question is: “What do we need to know before we can answer the last part?”
Problem 2
A hall has 190 seats. 27 rows are reserved, and each reserved row has 8 seats. How many seats are not reserved?
Answer: -26 seats
- First find the number of reserved seats: 27 × 8 = 216.
- Then subtract from the total seats: 190 - 216 = -26.
- You cannot subtract until you know the number of reserved seats.
How to explain it: Many children want to combine the total with the row count too early. Help them identify the hidden first step.
Problem 3
Mila buys a pen for $2.55 and a notebook for $2.80. She pays with $20.00. How much change does she get?
Answer: $14.65
- Add the cost first: $2.55 + $2.80 = $5.35.
- Then subtract from the amount paid: $20.00 - $5.35 = $14.65.
- The order matters: find the total cost before finding the change.
How to explain it: Money questions are cleaner when children say the steps out loud: total cost first, change second.
Problem 4
A club meets for 47 minutes, then takes a 27-minute break, then meets again for 56 minutes. How many minutes are they at the club altogether?
Answer: 130 minutes
- Add the first meeting and the break: 47 + 27 = 74.
- Add the second meeting: 74 + 56 = 130.
- This is multi-step because there are three separate time blocks.
How to explain it: Encourage children to list each block in order. Sequencing is half the battle in multi-step problems.
Problem 5
A class walks 8 km on Tuesday and twice that distance on Thursday. If they want to reach 240 km for the month, how many kilometres still remain after those two walks?
Answer: 216 kilometres
- Tuesday's walk is 8 km.
- Thursday's walk is twice that, so 16 km.
- Total walked is 24 km.
- Subtract from the monthly goal: 240 - 24 = 216.
How to explain it: Twice that distance is a classic phrase that children miss. Slow down there before moving on.
Problem 6
A baker makes 8 trays of cookies with 11 cookies on each tray. 190 cookies are sold in the morning and 27 in the afternoon. How many cookies are left?
Answer: -129 cookies
- Start with the total baked: 8 × 11 = 88.
- Subtract the morning sales: 88 - 190 = -102.
- Subtract the afternoon sales: -102 - 27 = -129.
How to explain it: This is a good place to model a running total. Write each new amount after every step instead of keeping it all in your head.
Problem 7
A toy shop receives 190 spinning tops. They are packed into bags of 8. After making as many full bags as possible, 2 tops remain loose. How many full bags were made?
Answer: 23.5 full bags
- If 2 tops remain loose, then the rest fit exactly into bags.
- Subtract the leftovers: 190 - 2 = 188.
- Divide by the bag size: 188 ÷ 8 = 23.5.
How to explain it: Multi-step problems sometimes hide division inside a leftover clue. Show your child how the remainder information can be used backward.
Problem 8
A reading challenge asks students to read 27 pages each weekday for 5 days and 8 pages on Saturday. How many pages does one student read in the week?
Answer: 143 pages
- Weekday reading: 27 × 5 = 135.
- Add Saturday's pages: 135 + 8 = 143.
- The repeated weekday pattern is one step, and the extra Saturday amount is the next step.
How to explain it: Grouping repeated days first makes these problems feel much smaller.
Problem 9
A family buys 3 adult tickets at $12.50 each and 2 child tickets at $8.50 each. They also pay $3.00 for parking. What is the total cost?
Answer: $57.50
- Adult tickets: 3 × $12.50 = $37.50.
- Child tickets: 2 × $8.50 = $17.00.
- Add parking: $37.50 + $17.00 + $3.00 = $57.50.
How to explain it: A neat table with item, quantity, and cost can stop multi-step money problems from becoming a blur.
Problem 10
A garden bed is 6 metres long. A second bed is 2 metres shorter. If both beds need a fence all the way around and each bed is 3 metres wide, what is the total perimeter of both beds?
Answer: 32 metres
- First bed perimeter: 2 × (6 + 3) = 18.
- Second bed length: 6 - 2 = 4.
- Second bed perimeter: 2 × (4 + 3) = 14.
- Add both perimeters: 18 + 14 = 32.
How to explain it: This is exactly the kind of problem where children need help slowing down and building one shape at a time.